Users browsing this thread: 1 Guest(s)
Vipershark (47) - Last updated Today, 07:45 AM
#16
(04-02-2010, 07:28 PM)TomGuycott Wrote:
(04-02-2010, 07:08 PM)bryan GT broyan Wrote: how the f does vipershark have like double my rep

Vipershark makes people laugh at his own expense
Thanked by:
#17
he doesn't even do that, i just feel bad for vipershark when he starts posting about anime. it hurts my heart to know how clueless one person really can be. rip vipershark you will be missed
skype: bryangtbroyan
Thanked by:
#18
Hue is one of the main properties of a color, defined technically (in the CIECAM02 model), as “the degree to which a stimulus can be described as similar to or different from stimuli that are described as red, green, blue, and yellow,”[1] (the unique hues). The other main correlates of color appearance are colorfulness, chroma, saturation, lightness, and brightness.

Usually, colors with the same hue are distinguished with adjectives referring to their lightness and/or chroma, such as with "light blue", "pastel blue", "vivid blue". Exceptions include brown, which is a dark orange,[2] and pink, a light red with reduced chroma.

In painting color theory, a hue refers to a pure color—one without tint or shade (added white or black pigment, respectively).[3]. A hue is an element of the color wheel. Hues are first processed in the brain in areas in the extended V4 called globs.[4][5]

Computing hue

In opponent color spaces in which two of the axes are perceptually orthogonal to lightness, such as CIE L*a*b* (CIELAB) and CIE L*u*v* (CIELUV), hue may be computed together with chroma by converting these coordinates from rectangular form to polar form. Hue is the angular component of the polar representation, while chroma is the radial component.

Specifically, in CIELAB:[6]

h_{ab} = \mathrm{atan2}(b^*, a^*)\;

while, analogously, in CIELUV:[6]

h_{uv} = \mathrm{atan2}(v^*, u^*) = \mathrm{atan2}(v', u')\;

Where, atan2 is a two-argument inverse tangent.
[edit] Computing hue from RGB

Preucil[7] describes a color hexagon, similar to a trilinear plot described by Evans, Hanson, and Brewer,[8] which may be used to compute hue from RGB. To place red at 0°, green at 120°, and blue at 240°, one may solve:

\tan h_{Preucil\ hexagon} = \frac{\sqrt{3}\cdot (G - B)}{2\cdot R - G - B}

He also used a polar plot, which he termed a color circle.[7] Using R, G, and B, rather than the R, G, and B densities Preucil used, one may compute hue angle using the following scheme: determine which of the six possible orderings of R, G, and B prevail, then apply the appropriate formula; see table below.
Thanked by: PrettyNier
#19
hahaha that's so funny pause not get the fuck out you cuntbag
[Image: detg1h.png]
Thanked by: PrettyNier
#20
that's Really Interesting
Thanked by: PrettyNier
#21
thanks for the hue-g post, flame! wahahahahahahaha! - wario
skype: bryangtbroyan
#22
vipershark you need to find a girl who's name doesn't end in .jpg






















p:
#23
(04-02-2010, 07:44 PM)bryan GT broyan Wrote:
(04-02-2010, 07:28 PM)TomGuycott Wrote: Vipershark makes people laugh

lmao no he doesn't, Tom "Bottom Tier" Guycott. good try though, maybe next time

I don't have to take this shit, I'm outta here.

[Image: ifbajp.gif]
Thanked by:
#24
(04-02-2010, 08:03 PM)TomGuycott Wrote: hmm im getting make fun of by bryan i better use one of these gifs i stole from his posts to seque out of this thread
Thanked by: PrettyNier
#25
(04-02-2010, 08:07 PM)sweet georgia brown Wrote:
(04-02-2010, 08:03 PM)TomGuycott Wrote: hmm im getting make fun of by bryan i better use one of these gifs i stole from his posts to seque out of this thread

God dammit, why can't you let me subtly say "I actually love you bryan" without being gay about it? Now the thread is overblown with the gay. And not the gay that I made with bad posts, I mean man love. Way to go.
Thanked by:
#26
this spamhaul needs more vipersharks or else we will all be brian.
Thanked by:
#27
(04-02-2010, 08:45 PM)Francisco Cifuentes Wrote: this spamhaul needs more vipersharks or else we will all be brian.

woah talk about a perfect world

and my name is literally in every one of my posts is it really that hard
skype: bryangtbroyan
Thanked by:
#28
it would be as perfect as everyone yelling at each other telling how shitty they are in an endless loop.
Thanked by:
#29
i am happy with my 10 rep

honest
Thanked by:
#30
(04-02-2010, 08:48 PM)Francisco Cifuentes Wrote: it would be as perfect as everyone yelling at each other telling how shitty they are in an endless loop.

we already do that though???? the revolution has already begun
skype: bryangtbroyan
Thanked by:


Forum Jump: